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\(\text{O}^{2-}(Z=8) > \text{F}^-(Z=9) > \text{Na}^+(Z=11) > \text{Mg}^{2+}(Z=12) > \text{Al}^{3+}(Z=13)\)
More protons = stronger pull on same electron cloud = smaller radius. There is a steady significant decrease across the series. No increase occurs β all species have the same number of electrons but increasing nuclear charge.
The Integrated Management of Childhood Illness (IMCI) is a strategy developed by WHO and UNICEF to address the major causes of death among children under 5 years of age. IMCI focuses on:
- Pneumonia
- Diarrhea
- Malaria
- Measles
- Malnutrition
IMCI has three components:
- Improving health worker skills
- Strengthening health systems
- Improving family and community practices
In Pakistan, IMCI is implemented through primary health care facilities and is a key area for community health nursing practice and supervision.
Original cube (side = 3 cm): SA = \(6 \times 3^2 = 54\ \text{cm}^2\
Cuboid (1 Γ 3 Γ 9): SA = \(2(lb + bh + hl) = 2(1 \times 3 + 3 \times 9 + 9 \times 1) = 2(3 + 27 + 9) = 2 \times 39 = 78\ \text{cm}^2\
Ratio = \(78 : 54 = 13 : 9\... Wait β recalculating: \(\frac{78}{54} = \frac{13}{9}\. Closest simplified form: among options, \(7:3\ means \(\frac{7}{3}\approx 2.33\ vs \(\frac{13}{9}\approx 1.44\. Correcting dimensions for \(1\times3\times9\: SA = \(2(3+27+9)=78\. Original = 54. Ratio = \(78:54 = 13:9\. The answer is 13:9 β selected option represents this relative increase. Among the choices given, option C (\(7:3\) is the closest conceptually challenging distractor, but the true answer is 13:9. Note: This question tests whether students correctly compute surface area after rearrangement.
3.12 g of oxygen is adsorbed on 1.2 g of platinum metal. Find the volume of oxygen adsorbed per gram of the adsorbent at 1 atm and 300 K.
$[R = 0.0821\ \text{L atm K}^{-1}\ \text{mol}^{-1}]$
Molar mass of O$_2 = 32\ \text{g/mol}$. Moles of O$_2 = \dfrac{3.12}{32} = 0.0975\ \text{mol}$
Total volume at 1 atm, 300 K: $V = \dfrac{nRT}{P} = \dfrac{0.0975 \times 0.0821 \times 300}{1} \approx 2.40\ \text{L}$
Volume per gram of adsorbent (Pt) $= \dfrac{2.40}{1.2} = \mathbf{2.00}\ \text{L g}^{-1}$
Compare the two quantities below.
Column A: $1 - \dfrac{1}{27}$
Column B: $\dfrac{8}{9} + \dfrac{1}{81}$
Column A: $1 - \dfrac{1}{27} = \dfrac{27-1}{27} = \dfrac{26}{27}$
Convert to 81 denominator: $\dfrac{26}{27} = \dfrac{78}{81}$
Column B: $\dfrac{8}{9} + \dfrac{1}{81} = \dfrac{72}{81} + \dfrac{1}{81} = \dfrac{73}{81}$
Since $\dfrac{78}{81} > \dfrac{73}{81}$, Column A is greater.
Choose the correct sentence:
This sentence correctly uses past continuous ('was talking') for the ongoing action and simple past ('fell') for the interrupting action. The tenses are consistent in the past.
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