Study questions platform-wide or filter by specific tests with correct answers revealed.
In Diabetic Ketoacidosis (DKA), insulin deficiency leads to:
- Excess fat breakdown → ketone body production
- Accumulation of ketoacids → metabolic acidosis
- Compensatory hyperventilation (Kussmaul breathing) → \\text{PaCO}_2 falls (respiratory compensation)
Expected ABG in DKA:
| Parameter | Value | Interpretation |
|---|---|---|
| pH | < 7.35 | Acidosis |
| \\text{PaCO}_2 | < 35 mmHg | Respiratory compensation (hyperventilation) |
| \\text{HCO}_3^- | < 18 mEq/L | Primary metabolic loss |
Option B (pH 7.28, PaCO₂ 28, HCO₃ 10) fits perfectly — metabolic acidosis with respiratory compensation.
Let $\omega$ be a complex number with $2\omega+1=z$ where $z=\sqrt{-3}$. If $\begin{vmatrix}1&1&1\\1&-\omega^2-1&\omega^2\\1&\omega^2&\omega^7\end{vmatrix}=3k$, find $k$.
Since $z=\sqrt{-3}=i\sqrt{3}$ and $2\omega+1=i\sqrt{3}$, so $\omega=\frac{-1+i\sqrt{3}}{2}=e^{2\pi i/3}$ (a primitive cube root of unity).
Properties: $\omega^3=1$, $1+\omega+\omega^2=0$, so $-\omega^2-1=\omega$ and $\omega^7=\omega$.
Matrix becomes: $\begin{vmatrix}1&1&1\\1&\omega&\omega^2\\1&\omega^2&\omega\end{vmatrix}$
This determinant $= 3(\omega-\omega^2)\cdot... $ After evaluation $= 3i\sqrt{3} = 3z$... so $k=z$.
Sign in to join the conversation and share your thoughts.
Log In to Comment