Study questions platform-wide or filter by specific tests with correct answers revealed.
A trader provided the following data:
| Item | Jan 1 ($) | Dec 31 ($) |
|---|---|---|
| Bank (Debit) | 4,240 | 6,320 |
| Cash balance | 264 | 271 |
During the year: Cheques issued were $19,950. All sales takings were banked except for $5,400 used for drawings and $7,200 for wages. Additionally, $3,000 was banked from the sale of a motor vehicle. Calculate total sales.
1. Cash banked from sales = Closing Bank ($6,320) + Cheques issued ($19,950) - Opening Bank ($4,240) - Sale of Asset ($3,000) = $19,030.
2. Total Sales = Banked Sales ($19,030) + Cash Drawings ($5,400) + Cash Wages ($7,200) + (Closing Cash $271 - Opening Cash $264) = $19,030 + $5,400 + $7,200 + $7 = $31,637.
Total number of electron pairs around the central atom in water (O) is:
Water has 2 bond pairs (O-H) and 2 lone pairs β total 4 electron pairs (tetrahedral electron geometry).
Which of the following compounds is the strongest acid?
Acidity of $\text{CHX}_3$ compounds depends on the electron-withdrawing ability of the substituents X, which stabilize the conjugate base carbanion $\text{CX}_3^-$.
- CN is an extremely strong electron-withdrawing group (by both induction and resonance).
- $\text{CH(CN)}_3$ has three CN groups, creating maximum negative charge delocalization on the carbanion β giving the most stable conjugate base.
- Halogens: electronegativity order is F > Cl > Br > I, so CHCl$_3$ > CHBr$_3$ > CHI$_3$ in acidity.
Overall: CH(CN)$_3$ is the strongest acid due to the powerful electron-withdrawing CN groups.
Sign in to join the conversation and share your thoughts.
Log In to Comment