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Which one of the following qualifies as a capital expenditure?
Capital expenditure is spending that improves, extends the life of, or adds value to a long-term asset. Renovating and upgrading a building increases its value and useful life โ this is capital expenditure. The other options are all revenue expenditures: carriage outwards, legal recovery fees, and wage bonuses are period costs that appear on the income statement and do not create lasting assets.
A projectile has initial velocity $(2\hat{i}+3\hat{j})\text{ m/s}$ at point A (at ground level). At point B (on the x-axis, same height as A), its velocity is:
Horizontal component is unchanged throughout: $v_x = 2\text{ m/s}$.
When the projectile returns to the same height, the vertical component reverses: $v_y = -3\text{ m/s}$.
Velocity at B $= \mathbf{2\hat{i} - 3\hat{j}}$
Compare the two quantities below.
Column A: $9^7$
Column B: $10{,}000{,}000$
Note that $10{,}000{,}000 = 10^7$.
Comparing $9^7$ vs $10^7$: since the base $9 < 10$ and both exponents are equal and positive, we have $9^7 < 10^7$.
Therefore Column B ($10^7$) is greater than Column A ($9^7$).
\(5(1)^2 - 4(1) - 1 = 5 - 4 - 1 = 0\)
Remainder \(= 0\).
Reduction: $Mn^{2+} + 2e^{-} \rightarrow Mn$ ($E^{0}_{red} = -1.18\text{ V}$)
Oxidation: $2Mn^{2+} \rightarrow 2Mn^{3+} + 2e^{-}$ ($E^{0}_{ox} = -1.51\text{ V}$)
$E^{0}_{cell} = E^{0}_{cathode} - E^{0}_{anode} = -1.18 - 1.51 = -2.69\text{ V}$. Since $E^{0}_{cell}$ is negative, the reaction is non-spontaneous.
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