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- B (Period 2): smallest
- Al (Period 3): larger than B
- Ga (Period 4): slightly smaller than Al due to d-block contraction (3d¹⁰ electrons offer poor shielding)
- In (Period 5): larger than Ga
- Tl (Period 6): largest
A ball is dropped from rest at $t = 0$. After 6 s, another ball is thrown downward from the same point with speed $v$. Both balls meet at $t = 18\text{ s}$. Find $v$ ($g = 10\text{ m/s}^2$).
Ball 1 falls for 18 s: $h_1 = \dfrac{1}{2}(10)(18)^2 = 1620\text{ m}$
Ball 2 falls for $18 - 6 = 12\text{ s}$: $h_2 = 12v + \dfrac{1}{2}(10)(12)^2 = 12v + 720$
Setting $h_1 = h_2$: $12v + 720 = 1620 \Rightarrow 12v = 900 \Rightarrow v = \mathbf{75\text{ m/s}}$
Before Maria changed jobs, her salary was 24 percent more than Julio's salary. After Maria changed jobs, her new salary was 24 percent less than her old salary.
Compare:
Column A: Julio's salary
Column B: Maria's new salary
Let Julio's salary be $J$ and Maria's old salary be $M_{old}$.
Given: $M_{old} = 1.24J$
Maria's new salary: $M_{new} = M_{old} - 0.24M_{old} = 0.76M_{old} = 0.76(1.24J) = 0.9424J$
Comparing:
- Column A: $J = 1.0J$
- Column B: $0.9424J$
Since $1.0 > 0.9424$, Column A (Julio's salary) is greater than Column B (Maria's new salary).
Therefore, Column A is greater.
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