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A missile is fired for maximum range with initial velocity $20\text{ m/s}$ ($g = 10\text{ m/s}^2$). The range of the missile is:
Maximum range occurs at $\theta = 45°$:
$R_{\max} = \dfrac{u^2}{g} = \dfrac{(20)^2}{10} = \mathbf{40\text{ m}}$
The product of upper-triangular matrices $\begin{pmatrix}1&k\\0&1\end{pmatrix}$ gives $\begin{pmatrix}1&\sum k\\0&1\end{pmatrix}$.
$\sum_{k=1}^{n-1}k = \dfrac{(n-1)n}{2} = 78 \Rightarrow n(n-1)=156 \Rightarrow n=13$
The inverse of $\begin{pmatrix}1&n\\0&1\end{pmatrix} = \begin{pmatrix}1&13\\0&1\end{pmatrix}$ is $\begin{pmatrix}1&-13\\0&1\end{pmatrix}$.
$S_n = \dfrac{q^{n+1}-1}{q-1}$. The LHS sum involves $\sum_{k=1}^{101}\binom{101}{k}S_{k-1}$.
After substituting and applying binomial theorem: the sum simplifies using $\sum \binom{101}{k}\frac{q^k-1}{q-1}$.
The result evaluates to $\alpha T_{100}$ where $\alpha = 2^{100}$.
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