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English QUESTION #2735

Which sentence correctly converts 'They completed the project' to PASSIVE VOICE?

The project is completed by them.
The project completed by them.
The project was completed by them.✔️
The project has been completed by them.

Correct Answer Logic:

Simple past active voice converts to simple past passive using was/were + past participle. 'The project was completed by them' is the correct conversion.

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English QUESTION #8324

Question 2

Tick the word SIMILAR in meaning to: Dubious

certain
doubtful✔️
rigorous
feeble

Correct Answer Logic:

Dubious means doubtful or uncertain.

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Chemistry QUESTION #7112

Question 3

In a galvanic cell represented by $Pt(s) | H_{2}(g, 1\text{ bar}) | HCl(aq) | AgCl(s) | Ag(s)$, the potential is $0.92\text{ V}$ at a specific concentration. If the standard reduction potential for the silver-silver chloride electrode is $0.22\text{ V}$, what is the $pH$ of the $HCl$ solution? (Assume $\frac{2.303RT}{F} = 0.06$)

$11.6$✔️
$10.5$
$9.4$
$12.1$

Correct Answer Logic:

The cell reaction is $\frac{1}{2}H_{2} + AgCl \rightarrow Ag + H^{+} + Cl^{-}$.
$E_{cell} = E^{0}_{cell} - 0.06 \log([H^{+}][Cl^{-}])$. Since $E^{0}_{H_{2}/H^{+}} = 0$, $E^{0}_{cell} = 0.22\text{ V}$.
$0.92 = 0.22 - 0.06 \log([H^{+}]^2)$ (assuming $[H^{+}] = [Cl^{-}]$).
$0.70 = -0.12 \log[H^{+}] = 0.12 \times pH$.
$pH = 0.70 / 0.06 \approx 11.6$.

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Verbal Reasoning QUESTION #8069

Question 4

$d = 5.03894$ and $\overline{d}$ is the decimal expression for $d$ rounded to the nearest thousandth.

Compare:

Column A: The number of decimal places where $d$ and $\overline{d}$ differ

Column B: 4

Column A is greater
Column B is greater✔️
The two quantities are equal
The relationship cannot be determined

Correct Answer Logic:

When we round $d = 5.03894$ to the nearest thousandth, we get $\overline{d} = 5.039$ (since the fourth decimal place is 9, which is $\geq 5$, we round up).

Comparing digit by digit:

Position 1 (units): both have 5 ✓
Position 2 (tenths): both have 0 ✓
Position 3 (hundredths): both have 3 ✓
Position 4 (thousandths): $d$ has 8, $\overline{d}$ has 9 ✗
Position 5 onwards: $d$ has 94, $\overline{d}$ has nothing

The positions where they differ are the thousandths place and beyond (positions 4, 5, 6...). If we count decimal places where values differ, we get 3 places (the thousandth, ten-thousandth, and hundred-thousandth positions).

Actually, re-reading: the question asks for decimal PLACES where they differ. Since $\overline{d}$ ends at thousandths, comparing through all decimal places in $d$: they differ at the 4th and 5th decimal positions. That's 2 places, which is less than 4.

Therefore Column B is greater.

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Chemistry QUESTION #5531

Question 5

For a reaction obeying the Arrhenius equation in the range $0°C < T < 300°C$: Plot I shows $k$ vs $E_a$ (decreasing curve), Plot II shows $k$ vs $T(°C)$ (increasing curve). Choose the correct option.

I is right but II is wrong
Both I and II are correct✔️
I is wrong but II is right
Both I and II are wrong

Correct Answer Logic:

From Arrhenius equation: $k = Ae^{-E_a/RT}$. As $E_a$ increases (at constant T), $k$ decreases — Plot I (k vs $E_a$ as a decreasing curve) is correct. As T increases (at constant $E_a$), $k$ increases exponentially — Plot II (k vs T as an increasing curve) is correct. Both plots are correct representations.

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Statistics QUESTION #1999

Question 6

The coefficient of determination $r^2$ in a simple linear regression is best interpreted as:

The slope of the regression line
The proportion of total variation in $Y$ explained by the linear relationship with $X$✔️
The correlation between residuals and fitted values
The ratio $\dfrac{SS_{xy}}{SS_{xx}}$

Correct Answer Logic:

$r^2 = \dfrac{SS_{reg}}{SS_{yy}} = 1 - \dfrac{SS_{res}}{SS_{yy}}$. It represents the fraction of variability in $Y$ that is accounted for (explained) by the linear regression on $X$. Values close to 1 indicate a strong linear fit.

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Urdu QUESTION #5156

Question 7

'بیچارے لوگ' کس کا ناول ہے؟

داستایوفسکی✔️
محمد حامد شاہد
حامد علی
ان میں سے کوئی نہیں

Correct Answer Logic:

بیچارے لوگ روسی مصنف داستایوفسکی کے ناول کا اردو ترجمہ ہے۔

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Mathematics QUESTION #7436

Question 8

Let $\vec{a}, \vec{b}$ and $\vec{c}$ be three non-zero vectors such that no two of them are collinear and $(\vec{a} \times \vec{b}) \times \vec{c} = \frac{1}{3}|\vec{b}||\vec{c}|\vec{a}$. If θ is the angle between vectors $\vec{b}$ and $\vec{c}$, then a value of sin θ is:

$\frac{2\sqrt{2}}{3}$✔️
$\frac{-\sqrt{2}}{3}$
$\frac{2}{3}$
$\frac{-2\sqrt{3}}{3}$

Correct Answer Logic:

Using the vector triple product formula: $(\vec{a} \times \vec{b}) \times \vec{c} = (\vec{a} \cdot \vec{c})\vec{b} - (\vec{b} \cdot \vec{c})\vec{a}$. Given this equals $\frac{1}{3}|\vec{b}||\vec{c}|\vec{a}$, we have $(\vec{a} \cdot \vec{c})\vec{b} - (\vec{b} \cdot \vec{c})\vec{a} = \frac{1}{3}|\vec{b}||\vec{c}|\vec{a}$. Since $\vec{a}$ and $\vec{b}$ are non-collinear, comparing coefficients: $\vec{b} \cdot \vec{c} = -\frac{1}{3}|\vec{b}||\vec{c}|$, which gives $\cos\theta = -\frac{1}{3}$. Therefore, $\sin\theta = \sqrt{1-\cos^2\theta} = \sqrt{1-\frac{1}{9}} = \sqrt{\frac{8}{9}} = \frac{2\sqrt{2}}{3}$.

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English QUESTION #8321

Question 9

There was so much smoke in the room that I could hardly _______.

Breath
Breathe✔️
Breathing
Breathless

Correct Answer Logic:

'Breathe' is the verb meaning to inhale and exhale.

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Information Technology QUESTION #1117

Question 10

Which of the following is the false statement in C language?

static a=10;
static int func (int);
static static int a;✔️
None of these

Correct Answer Logic:

In C, you cannot use the same storage class specifier multiple times for a single variable declaration. static static is syntactically invalid.

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Paper-II (Pharmacognosy and Pharmaceutics-I) QUESTION #3062

Question 11

What is the 'HLB Value' system used for?

Measuring drug potency
Classifying surfactants for emulsions✔️
Calculating doses for the elderly
Determining glass type

Correct Answer Logic:

The Hydrophilic-Lipophilic Balance (HLB) value helps select the right emulsifying agent.

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Statistics QUESTION #1990

Question 12

For the Poisson distribution with parameter $\lambda$, which of the following statements is INCORRECT?

Mean = Variance = $\lambda$
The distribution is always positively skewed for finite $\lambda$
The mgf is $M(t) = e^{\lambda(e^t - 1)}$
As $\lambda \to \infty$, the Poisson distribution approaches the t-distribution✔️

Correct Answer Logic:

The mean, variance, and mgf statements are all correct properties of the Poisson distribution. As $\lambda \to \infty$, the Poisson distribution approaches the NORMAL distribution (not the t-distribution), by the Central Limit Theorem. This is what makes statement (D) incorrect.

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Chemistry QUESTION #7517

Question 13

A metal oxide has the formula M$_{0.98}$O. The metal M exists as M$^{2+}$ and M$^{3+}$ ions. What fraction of the metal exists as M$^{3+}$?

7.01%
4.08%✔️
6.05%
5.08%

Correct Answer Logic:

Let $x$ = fraction of M as M$^{3+}$, $(0.98 - x)$ = fraction as M$^{2+}$.

Charge balance (O$^{2-}$ contributes $-2$): $2(0.98-x) + 3x = 2$

$1.96 - 2x + 3x = 2$

$x = 0.04$

Fraction of M as M$^{3+}$ $= \dfrac{0.04}{0.98} \times 100 \approx \mathbf{4.08\%}$

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General Knowledge QUESTION #8680

Question 14

What does 'macroeconomics' study?

Branch of economics that studies the economy as a whole✔️
Fundamental system of mathematics
Financial system at provincial level
Changes in prices

Correct Answer Logic:

Macroeconomics studies aggregate economic behavior.

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Physics QUESTION #7083

Question 15

A solid sphere (radius $r$, bulk modulus $K$) is in a liquid. A mass $m$ is placed on a piston of area $a$ to compress the liquid. Find the fractional decrease in radius $\frac{dr}{r}$.

$\frac{mg}{3Ka}$✔️
$\frac{mg}{Ka}$
$\frac{Ka}{mg}$
$\frac{3Ka}{mg}$

Correct Answer Logic:

Bulk Modulus $K = \frac{\Delta P}{-\Delta V/V}$.

The change in pressure is $\Delta P = \frac{mg}{a}$.
The fractional change in volume for a sphere is $\frac{\Delta V}{V} = 3\frac{dr}{r}$.
$K = \frac{mg/a}{3dr/r} \implies \frac{dr}{r} = \frac{mg}{3Ka}$.

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Civil / Architecture QUESTION #2347

Question 16

Sound Pressure Level (SPL) $L_p$ in decibels relative to reference pressure $p_0 = 20\,\mu\text{Pa}$ is defined as:

$L_p = 10\log_{10}\!\left(\dfrac{p}{p_0}\right) \text{ dB}$
$L_p = 20\log_{10}\!\left(\dfrac{p}{p_0}\right) \text{ dB}$✔️
$L_p = 10\log_{10}\!\left(\dfrac{I}{I_0}\right) \text{ dB where } I_0 = 10^{-12}\,\text{W/m}^2$
$L_p = 20\log_{10}\!\left(\dfrac{p_0}{p}\right) \text{ dB}$

Correct Answer Logic:

SPL is defined as $L_p = 20\log_{10}\!\left(\dfrac{p}{p_0}\right)$ dB, since pressure is an amplitude (not power) quantity. Note that Option C defines Sound Intensity Level $L_I = 10\log_{10}(I/I_0)$, which numerically equals SPL in a free field for plane waves. Options A would be correct for power ratios. Option D is inverted and gives negative values.

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Accounting & Finance QUESTION #9633

Question 17

An asset purchased for Rs. 150,000 with an estimated life of 10 years is depreciated on the straight-line method. After Year 2, it is classified as 'Written Down Value'. What is the Written Down Value at the end of Year 2, and what is the annual depreciation charge?

WDV = Rs. 130,000; Annual depreciation = Rs. 15,000
WDV = Rs. 120,000; Annual depreciation = Rs. 15,000✔️
WDV = Rs. 135,000; Annual depreciation = Rs. 7,500
WDV = Rs. 120,000; Annual depreciation = Rs. 30,000

Correct Answer Logic:

Annual depreciation (SLM) = Cost ÷ Estimated life = 150,000 ÷ 10 = Rs. 15,000. Accumulated depreciation after Year 2 = 15,000 × 2 = Rs. 30,000. Written Down Value = Cost – Accumulated Depreciation = 150,000 – 30,000 = Rs. 120,000.

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Dairy Food Science and Technology QUESTION #5987

Question 18

The function of 'cutting' the rennet curd into cubes in cheese making is to:

Add flavor compounds to the curd surface
Increase the surface area of curd to facilitate rapid and controlled whey expulsion (syneresis), with smaller cuts producing drier cheeses (e.g. Parmesan: pea-sized cubes; Camembert: large irregular cubes)✔️
Allow brine to penetrate the curd for salting
Mix starter culture evenly throughout the curd

Correct Answer Logic:

Curd cutting creates more surface area for whey drainage. Curd cube size directly determines final cheese moisture: smaller cuts $\rightarrow$ more surface area $\rightarrow$ faster whey expulsion $\rightarrow$ lower moisture (hard cheeses like Parmesan: pea-sized cuts); larger cuts $\rightarrow$ slower drainage $\rightarrow$ higher moisture (soft cheeses like Camembert).

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