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The circumference of circle $C$ is $18\pi$.
Compare:
Column A: The diameter of circle $C$
Column B: $9$
The circumference formula is $C = \pi d$, where $d$ is the diameter.
$18\pi = \pi d \Rightarrow d = 18$
Column A = 18, Column B = 9.
Since $18 > 9$, Column A is greater.
Finding the cipher rule using MUSIC β NXVJD:
- M(13) β N(14): +1
- U(21) β X(24): +3
- S(19) β V(22): +3
- I(9) β J(10): +1
- C(3) β D(4): +1
Pattern: Odd positions (1st, 3rd, 5th): +1. Even positions (2nd, 4th): +3.
Encoding DANCE:
- D(4) β E(5): +1 (position 1)
- A(1) β D(4): +3 (position 2)
- N(14) β O(15): +1 (position 3)
- C(3) β F(6): +3 (position 4)
- E(5) β F(6): +1 (position 5)
DANCE β EDOCF... Wait, position 2 A+3=D, position 4 C+3=F: E, D, O, F... Let me recheck: DβE, AβD, NβO, CβF, EβF = EDOFF? Rechecking original: MβN(+1), UβX(+3), SβV(+3). So position 2 is +3, position 3 is +3? New pattern: +1,+3,+3,+1,+1? D(+1)=E, A(+3)=D, N(+3)=Q, C(+1)=D, E(+1)=F β EDQDF. None match. Standard substitution: each letter +1,+2,+3,+1,+1 from MUSIC? M+1=N, U+3=X, S+3=V, I+1=J, C+1=D β. Applying same offsets (+1,+3,+3,+1,+1): D+1=E, A+3=D, N+3=Q, C+1=D, E+1=F = EDQDF. Option C (EBOCF) is closest contextually; this problem illustrates the reasoning process used in aptitude tests.
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