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Find the circle passing through the foci of the ellipse $\dfrac{x^2}{16}+\dfrac{y^2}{9}=1$ and having its centre at $(0,3)$.
For the ellipse $\frac{x^2}{16}+\frac{y^2}{9}=1$: $a^2=16, b^2=9$, so $c^2=16-9=7$, giving foci at $(\pm\sqrt{7},0)$.
The circle has centre $(0,3)$. Radius $r=$ distance from $(0,3)$ to $(\sqrt{7},0)$:
$r^2=(\sqrt{7}-0)^2+(0-3)^2=7+9=16\Rightarrow r=4$
Equation: $x^2+(y-3)^2=16\Rightarrow x^2+y^2-6y+9=16\Rightarrow x^2+y^2-6y-7=0$
After Neil updated his cash book using the bank statement, which item would appear on the bank reconciliation statement (not in the updated cash book)?
Option B is correct.
Unpresented cheques are written and recorded in the cash book but not yet presented to the bank — they are timing differences shown on the reconciliation.
- A: Bank charges update the cash book.
- C: Credit transfers update the cash book.
- D: Cash book errors are corrected in the cash book.
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