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- First, find cell constant ($G^*$): $G^* = \kappa \times R = 1.4 \times 50 = 70\text{ m}^{-1}$.
- Then find conductivity ($\kappa$) for $0.5\text{ M}$: $\kappa = G^*/R = 70/280 = 0.25\text{ S m}^{-1}$.
- Molar conductivity $\Lambda_m = \frac{\kappa}{1000 \times M} = \frac{0.25}{1000 \times 0.5} = 5 \times 10^{-4}\text{ S m}^{2}\text{ mol}^{-1}$.
Sharks belong to which class of vertebrates?
Class Chondrichthyes includes cartilaginous fish (sharks, rays). Osteichthyes are bony fish. Echinodermata are starfish etc.; Urochordata are tunicates.
Which of the following is equal to $\frac{1}{4}$ of 0.01 percent?
First, convert 0.01 percent to a decimal: $0.01\% = \frac{0.01}{100} = 0.0001$
Now find $\frac{1}{4}$ of this value:
$\frac{1}{4} \times 0.0001 = 0.000025$
Therefore, the answer is $0.000025$.
What is the primary outcome of crossing over during prophase I of meiosis?
Crossing over exchanges genetic material between non-sister chromatids of homologous chromosomes, producing new allele combinations (recombination) and increasing genetic variation.
For a linear scale, the temperature $T$ is related to reading $x$ by: $\frac{T - T_{ice}}{T_{steam} - T_{ice}} = \frac{x - x_{ice}}{x_{steam} - x_{ice}}$
$\frac{T - 0}{100 - 0} = \frac{x_0/2 - x_0/3}{x_0 - x_0/3}$
$\frac{T}{100} = \frac{x_0/6}{2x_0/3} = \frac{1}{6} \times \frac{3}{2} = \frac{1}{4}$
$T = \frac{100}{4} = 25^\circ\text{C}$.
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