This definition of curriculum is attributed to H. Rugg, who emphasized that the curriculum extends beyond formal classroom instruction to include all school-directed activities and experiences. This broad view aligns with modern holistic definitions of curriculum.

Correct Answer: C — H. Rugg.

• Spring constant $k$: $F = kx \Rightarrow [k] = \frac{[F]}{[x]} = \frac{MLT^{-2}}{L} = MT^{-2} = M^1L^0T^{-2}$ → (3)
• Pascal (pressure): $[P] = \frac{Force}{Area} = \frac{MLT^{-2}}{L^2} = ML^{-1}T^{-2} = M^1L^{-1}T^{-2}$ → (4)
• Hertz (frequency): $[f] = T^{-1} = M^0L^0T^{-1}$ → (2)
• Joule (energy): $[E] = ML^2T^{-2} = M^1L^2T^{-2}$ → (1)

Correct match: A-3, B-4, C-2, D-1

Average time between collisions $\tau$ is given by $\tau = \frac{\lambda}{v_{rms}}$, where $\lambda$ is the mean free path.

1. $\lambda \propto \frac{1}{n} \propto V$ (where $n$ is number density).
2. $v_{rms} \propto \sqrt{T}$.
3. For an adiabatic process, $TV^{\gamma-1} = \text{constant}$, so $T \propto V^{1-\gamma}$ and $\sqrt{T} \propto V^{\frac{1-\gamma}{2}}$.

Therefore, $\tau \propto \frac{V}{V^{\frac{1-\gamma}{2}}} = V^{1 - \frac{1-\gamma}{2}} = V^{\frac{2-1+\gamma}{2}} = V^{\frac{\gamma+1}{2}}$.
Hence, $q = \frac{\gamma+1}{2}$.

• $P_{1} = 35 \text{ psi}$, $T_{1} = 27 + 273 = 300 \text{ K}$
• $P_{2} = 40 \text{ psi}$, $T_{2} = ?$
• $35/300 = 40/T_{2}$
• $T_{2} = (40 \times 300) / 35 \approx 342.8 \text{ K}$
• Converting to Celsius: $342.8 - 273 = 69.8^{\circ}\text{C} \approx 70^{\circ}\text{C}$