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The thermal stress required to keep the length constant is given by the formula:
- $\text{Stress} = Y \alpha \Delta T$
- Substituting the values: $\text{Stress} = (2 \times 10^{11}) \times (1.1 \times 10^{-5}) \times 100$
- $\text{Stress} = 2.2 \times 10^{8}\text{ Pa}$
Pressure is equivalent to the stress applied at the ends.
Initial intensity $I$. After A, $I_A = I/2$. Since $I_B$ is also $I/2$, axes of A and B are parallel ($\theta_{AB} = 0$).
Insert C at angle $\phi$ to A. Then angle between C and B is also $\phi$.
Final intensity $I' = I_A \cos^2 \phi \cos^2 \phi = \frac{I}{2} \cos^4 \phi$.
Given $\frac{I}{2} \cos^4 \phi = \frac{I}{8} \implies \cos^4 \phi = \frac{1}{4} \implies \cos^2 \phi = \frac{1}{2}$.
Thus, $\cos \phi = \frac{1}{\sqrt{2}} \implies \phi = 45^\circ$.
Asim is now three times as old as Irfan. After 10 years, Asim will be twice as old as Irfan. Asim’s at this time is:
- 61 ✓ (prime)
- 67 ✓ (prime)
- 71 ✓ (prime)
- 73 ✓ (prime)
Speed of sound in ideal gas does NOT depend on:
For ideal gas, v = √(γRT/M). Pressure has no effect at constant temperature; moisture slightly affects density but the question says ideal gas: strictly, pressure independent.
Total cost data: 600 units = $4,200; 800 units = $5,200. What is the fixed cost per unit at each level?
| Option | For 600 units ($) | For 800 units ($) |
|---|---|---|
| A | 2.00 | 1.50 |
| B | 2.00 | 2.00 |
| C | 5.00 | 5.00 |
| D | 6.50 | 7.00 |
Option A is correct.
Variable cost per unit = ($5,200 − $4,200) ÷ 200 = $5
Fixed costs = $4,200 − (600 × $5) = $1,200
At 600 units: $1,200 ÷ 600 = $2.00; At 800 units: $1,200 ÷ 800 = $1.50
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