The sentence says the biography is laudatory (full of praise) yet still fails to capture Shaw’s essence. The two blanks set up a paradox.

Blank (i): The biography is about Shaw — it discusses him. The more he is discussed, the more elusive his true self becomes. “Disparaged” or “disregarded” would not logically follow from a laudatory biography that is earnestly trying to capture his personality.

Blank (ii): The sentence sets up a paradox — more discussion leads to less understanding. So the true self must disappear (become harder to find), not emerge or coalesce.

• “Emerge” would mean we understand him better — the opposite of the intended meaning.
• “Coalesce” means to come together — also contradicts the idea of failing to capture his essence.

Correct Answers: Blank (i) = A (discussed), Blank (ii) = D (disappear).

Step 1 — Find molarity of HCl:
$\text{Na}_2\text{CO}_3 + 2\text{HCl} \to 2\text{NaCl} + \text{H}_2\text{O} + \text{CO}_2$
Moles Na$_2$CO$_3 = 0.030 \times 0.1 = 3\times10^{-3}\ \text{mol}$
Moles HCl needed $= 2 \times 3\times10^{-3} = 6\times10^{-3}\ \text{mol}$
$M_{\text{HCl}} = \dfrac{6\times10^{-3}}{0.025} = 0.24\ \text{M}$

Step 2 — Volume for NaOH:
$\text{NaOH} + \text{HCl} \to \text{NaCl} + \text{H}_2\text{O}$
Moles NaOH $= 0.030 \times 0.2 = 6\times10^{-3}\ \text{mol}$
$V_{\text{HCl}} = \dfrac{6\times10^{-3}}{0.24} = 0.025\ \text{L} = \mathbf{25\ \text{mL}}$

Calculate each parenthesis separately:

First: $(19 - 18 - 17 - 16) = 19 - 18 - 17 - 16 = 1 - 17 - 16 = -16 - 16 = -32$

Second: $(20 - 19 - 18 - 17) = 20 - 19 - 18 - 17 = 1 - 18 - 17 = -17 - 17 = -34$

Now subtract: $(-32) - (-34) = -32 + 34 = 2$

Wait, let me recalculate more carefully:

$(19 - 18 - 17 - 16) = 19 - 51 = -32$

$(20 - 19 - 18 - 17) = 20 - 54 = -34$

$(-32) - (-34) = -32 + 34 = 2$

Hmm, 2 is not among the options. Let me check the arithmetic again:

$19 - 18 = 1$, $1 - 17 = -16$, $-16 - 16 = -32$ ✓

$20 - 19 = 1$, $1 - 18 = -17$, $-17 - 17 = -34$ ✓

$-32 - (-34) = 2$

Since the given answer is D, which corresponds to index 3 (value 1), there may be an error in my reading or the answer key. But mathematically, the answer is 2.

$\cos\alpha=3/5 \Rightarrow \sin\alpha=4/5,\ \tan\alpha=4/3$.

$\tan\beta=1/3$.

$\tan(\alpha-\beta)=\dfrac{4/3-1/3}{1+(4/3)(1/3)}=\dfrac{1}{1+4/9}=\dfrac{1}{13/9}=\dfrac{9}{13}$

Hmm — but the options show $9/(5\sqrt{10})$. Let me recheck: $\dfrac{4/3-1/3}{1+4/9}=\dfrac{3/3}{13/9}=\dfrac{1\cdot9}{13}=\dfrac{9}{13}$. This doesn't match the options exactly. The official answer is $\tan^{-1}(9/(5\sqrt{10}))$, corresponding to a slightly different computation path using $\sin$ and $\cos$ directly.