Study questions platform-wide or filter by specific tests with correct answers revealed.
In the right triangle shown, the right angle is at the bottom-left corner, with one leg labeled $x$ (vertical) and the other leg labeled $y$ (horizontal), and the angle at the bottom-right is $50°$.
Compare:
Quantity A: $\dfrac{x}{y}$
Quantity B: $1$
In the right triangle, the right angle is at the bottom-left. The angle at the bottom-right is $50°$, which means the angle at the top is $180° - 90° - 50° = 40°$.
The side opposite the $50°$ angle is $x$ (vertical leg), and the side opposite the $40°$ angle is $y$ (horizontal leg).
Since the angle opposite $x$ ($50°$) is greater than the angle opposite $y$ ($40°$), it follows that $x > y$.
Therefore $\dfrac{x}{y} > 1$, so Quantity A is greater.
Alternatively: $\tan(50°) = \dfrac{x}{y}$, and $\tan(50°) \approx 1.19 > 1$.
A fabric store sells material at \$8.00 per yard, but only in whole-yard increments. Each of 3 curtains requires 1.6 yards of fabric, and all the fabric is bought as one continuous piece. What is the total purchase cost?
Total fabric needed: $3 \times 1.6 = 4.8$ yards.
Since fabric is sold only in whole-yard increments, you must purchase $5$ full yards (round up from 4.8).
Total cost $= 5 \times \$8.00 = \mathbf{\$40.00}$.
Evidence-Based VAP Prevention Bundle (IHI):
| Intervention | Rationale |
|---|---|
| Head of bed elevation \(30 - 45°\) | Reduces aspiration of gastric contents |
| Daily Sedation Vacation (SAT) | Reduces duration of mechanical ventilation |
| Oral care with Chlorhexidine 0.12% | Reduces oropharyngeal colonization |
| Subglottic secretion drainage | Removes pooled secretions above ETT cuff |
| DVT prophylaxis | Component of IHI ventilator bundle |
| PUD prophylaxis | H2 blockers or PPIs (component of bundle) |
Max velocity reached: $v_{\max} = \alpha t_1$
Distance in acceleration phase: $s_1 = \dfrac{1}{2}\alpha t_1^2$
Distance in deceleration phase: $s_2 = \dfrac{1}{2}v_{\max}\,t_2 = \dfrac{1}{2}\alpha t_1 t_2$
Ratio: $\dfrac{s_1}{s_2} = \dfrac{\frac{1}{2}\alpha t_1^2}{\frac{1}{2}\alpha t_1 t_2} = \mathbf{\dfrac{t_1}{t_2}}$
Sign in to join the conversation and share your thoughts.
Log In to Comment