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The time period of a pendulum is $T = 2\pi\sqrt{\frac{L}{g}}$, so $L \propto T^2$.
- Initial length: $L = kT^2$
- New length: $L + \Delta L = k T_M^2$
- Strain: $\frac{\Delta L}{L} = \frac{T_M^2 - T^2}{T^2} = (\frac{T_M}{T})^2 - 1$
- From $Y = \frac{\text{Stress}}{\text{Strain}} = \frac{Mg/A}{\Delta L/L}$
- Therefore, $\frac{1}{Y} = \frac{\Delta L/L}{Mg/A} = [(\frac{T_M}{T})^2 - 1]\frac{A}{Mg}$
The four dielectrics fill four quadrants. Each half of the plate area (left and right halves, each of width $d/2$) acts as two capacitors in series (top and bottom dielectrics), and these two series combinations are in parallel.
More directly using the standard result for this arrangement:
$K_{eff} = \frac{(K_1+K_2)(K_3+K_4)}{K_1+K_2+K_3+K_4}$
This comes from treating left column ($K_1, K_3$ in series) in parallel with right column ($K_2, K_4$ in series), where each column occupies half the area and full thickness $d$, but each dielectric occupies half the thickness $d/2$.
In a certain shop, notebooks that normally sell for 59 cents each are on sale at 2 for 99 cents. How much can be saved by purchasing 10 of these notebooks at the sale price?
Normal price for 10 notebooks: $10 \times 59\text{¢} = 590\text{¢} = \$5.90$
Sale: 2 notebooks for 99¢, so 10 notebooks cost $5 \times 99\text{¢} = 495\text{¢} = \$4.95$
Savings $= \$5.90 - \$4.95 = \$0.95$
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