Option B is correct.

Unpresented cheques are written and recorded in the cash book but not yet presented to the bank — they are timing differences shown on the reconciliation.

• A: Bank charges update the cash book.
• C: Credit transfers update the cash book.
• D: Cash book errors are corrected in the cash book.

At the highest point, only horizontal velocity remains: $v_x = u\cos45° = \dfrac{u}{\sqrt{2}}$

$KE_{\text{top}} = \dfrac{1}{2}mv_x^2 = \dfrac{1}{2}m\cdot\dfrac{u^2}{2} = \dfrac{1}{2}\cdot\dfrac{1}{2}mu^2 = \mathbf{\dfrac{E}{2}}$

The three slabs are placed side-by-side (parallel combination), each occupying one-third of the area $A/3$ and the full separation $d$.

Total capacitance:

$C = \frac{\varepsilon_0 (A/3)}{d}(K_1 + K_2 + K_3) = \frac{\varepsilon_0 A}{3d}(10+12+14) = \frac{36\varepsilon_0 A}{3d} = \frac{12\varepsilon_0 A}{d}$

For a single dielectric $K$:

$C = \frac{K\varepsilon_0 A}{d}$

$\Rightarrow K = 12$

The equivalent dielectric constant is simply the arithmetic mean: $(10+12+14)/3 = 12$.

Bulk modulus $K = \rho \frac{dP}{d\rho}$.

• Rearranging for change in density $d\rho$: $d\rho = \frac{\rho dP}{K}$
• Given $dP = P$, the increase is $\frac{\rho P}{K}$.