Study questions platform-wide or filter by specific tests with correct answers revealed.
Of the following, which is closest to $\sqrt[3]{30}$?
Estimate by testing perfect cubes:
- $2^3 = 8$
- $3^3 = 27$
- $4^3 = 64$
Since $27 < 30 < 64$, we know $3 < \sqrt[3]{30} < 4$.
$30$ is much closer to $27$ than to $64$, so $\sqrt[3]{30}$ is closer to $3$ than to $4$.
More precisely: $\sqrt[3]{30} \approx 3.107$
Among the options $\{6, 5, 4, 3\}$, the value $3$ is closest.
Two projectiles fired from the same point with equal speed at $60°$ and $30°$. Which statement is true?
$60°$ and $30°$ are complementary angles, so $\sin(2\times60°) = \sin120° = \sin60° = \sin(2\times30°)$.
Range $R = \dfrac{u^2\sin2\theta}{g}$ is the same for both. Heights and times of flight differ.
$n$ is an even integer and a multiple of 3.
Compare:
Column A: The remainder when $n$ is divided by 12
Column B: 6
Since $n$ is even and a multiple of 3, $n$ must be a multiple of $\text{lcm}(2, 3) = 6$.
So $n = 6k$ for some integer $k$.
When we divide $n = 6k$ by 12:
- If $k$ is even (say $k = 2m$): $n = 12m$, remainder = 0
- If $k$ is odd (say $k = 2m + 1$): $n = 6(2m + 1) = 12m + 6$, remainder = 6
So the remainder when $n$ is divided by 12 can be either 0 or 6.
Since Column A could be 0 (less than 6) or 6 (equal to 6), the relationship cannot be determined.
Sign in to join the conversation and share your thoughts.
Log In to Comment