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A recently released, praise-filled biography of George Bernard Shaw fails, much like its predecessors, to truly capture the essence of his personality: the more he is (i)_____, the more his true self seems to (ii)_____.
| Blank (i) | Blank (ii) |
|---|---|
| A. discussed | D. disappear |
| B. disparaged | E. emerge |
| C. disregarded | F. coalesce |
The sentence says the biography is laudatory (full of praise) yet still fails to capture Shaw’s essence. The two blanks set up a paradox.
Blank (i): The biography is about Shaw — it discusses him. The more he is discussed, the more elusive his true self becomes. “Disparaged” or “disregarded” would not logically follow from a laudatory biography that is earnestly trying to capture his personality.
Blank (ii): The sentence sets up a paradox — more discussion leads to less understanding. So the true self must disappear (become harder to find), not emerge or coalesce.
- “Emerge” would mean we understand him better — the opposite of the intended meaning.
- “Coalesce” means to come together — also contradicts the idea of failing to capture his essence.
Correct Answers: Blank (i) = A (discussed), Blank (ii) = D (disappear).
A compound with molecular mass 180 is acylated with CH$_3$COCl to yield a compound with molecular mass 390. How many amino ($-\text{NH}_2$) groups does the original compound contain?
Acylation: each $-\text{NH}_2$ reacts with CH$_3$COCl to introduce a $-\text{COCH}_3$ group ($M = 42$) and release HCl.
Net mass added per amino group $= 42 - 1 = 42$ (the $-H$ is replaced by $-\text{COCH}_3$)
Wait — each NH$_2$ + CH$_3$COCl → NH$\cdot$COCH$_3$ + HCl. Mass change per group $= 42 - 1 = +41$... more precisely: $-NH_2$ (16) becomes $-NHCOCH_3$ (58): increase = 42.
Increase in mass $= 390 - 180 = 210$
Number of amino groups $= \dfrac{210}{42} = \mathbf{5}$
Reduction: $Mn^{2+} + 2e^{-} \rightarrow Mn$ ($E^{0}_{red} = -1.18\text{ V}$)
Oxidation: $2Mn^{2+} \rightarrow 2Mn^{3+} + 2e^{-}$ ($E^{0}_{ox} = -1.51\text{ V}$)
$E^{0}_{cell} = E^{0}_{cathode} - E^{0}_{anode} = -1.18 - 1.51 = -2.69\text{ V}$. Since $E^{0}_{cell}$ is negative, the reaction is non-spontaneous.
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