Study questions platform-wide or filter by specific tests with correct answers revealed.
Since quantities added or subtracted must have the same dimensions, $\dfrac{a}{V^2}$ must have the same dimensions as pressure $P$.
$[P] = [ML^{-1}T^{-2}]$ and $[V^2] = [L^6]$
Therefore: $[a] = [P][V^2] = [ML^{-1}T^{-2}][L^6] = [ML^5T^{-2}]$
Let $x$ and $m$ be positive numbers, where $m$ is a multiple of 3. Compare:
Quantity A: $\dfrac{x^m}{x^3}$
Quantity B: $x^{m/3}$
Simplify Quantity A: $\dfrac{x^m}{x^3} = x^{m-3}$.
Quantity B: $x^{m/3}$.
We need to compare $x^{m-3}$ with $x^{m/3}$. The relationship depends on the base $x$ and the exponent comparison.
Case 1: $x = 1$. Both quantities $= 1$. Equal.
Case 2: $x = 2,\ m = 6$. Qty A $= 2^{6-3} = 2^3 = 8$. Qty B $= 2^{6/3} = 2^2 = 4$. A > B.
Case 3: $x = 2,\ m = 3$. Qty A $= 2^{3-3} = 2^0 = 1$. Qty B $= 2^{3/3} = 2^1 = 2$. B > A.
Because different values give different results, the relationship cannot be determined.
\\text{CBR} = ?
The Crude Birth Rate (CBR) is calculated as:
\\text{CBR} = \\frac{\\text{Number of live births in a year}}{\\text{Mid-year total population}} \\times 1000
It is expressed per 1,000 population. Pakistan's CBR is approximately 26–28 per 1,000 population.
Comparison with other fertility measures:
- General Fertility Rate (GFR) uses women aged 15–49 as denominator
- Total Fertility Rate (TFR) is the average number of children a woman would have in her lifetime
- Option 3 is the formula for Crude Death Rate (CDR)
Five observations have mean $= 4$ and variance $= 5.2$. Three of the observations are $3, 4, 4$. Find the absolute difference between the remaining two observations.
Step 1 — Find the sum: $\sum x_i = 5\times4=20$. Known three: $3+4+4=11$. So $x_4+x_5=9$.
Step 2 — Find sum of squares: Variance $=\frac{\sum x_i^2}{n}-\bar{x}^2 \Rightarrow \frac{\sum x_i^2}{5}-16=5.2 \Rightarrow \sum x_i^2=106$.
Known: $3^2+4^2+4^2=9+16+16=41$. So $x_4^2+x_5^2=65$.
Step 3 — Solve: $x_4+x_5=9$ and $x_4^2+x_5^2=65$.
$(x_4+x_5)^2=81 \Rightarrow 2x_4x_5=81-65=16 \Rightarrow x_4x_5=8$.
$(x_4-x_5)^2=(x_4+x_5)^2-4x_4x_5=81-32=49$
$|x_4-x_5|=\mathbf{7}$
Sign in to join the conversation and share your thoughts.
Log In to Comment