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\(E = \dfrac{6.63 \times 10^{-34} \times 3 \times 10^8}{45 \times 10^{-9}}\)
\(= \dfrac{19.89 \times 10^{-26}}{45 \times 10^{-9}}\)
\(= \dfrac{19.89}{45} \times 10^{-17}\)
\(= 0.442 \times 10^{-17} = 4.42 \times 10^{-18}\) J
This energy (in UV range) is enough to ionise hydrogen from ground state (\(13.6\) eV \(= 2.18 \times 10^{-18}\) J).
A graduating class has 236 students. Among them, 142 enrolled in algebra and 121 enrolled in chemistry. What is the greatest possible number of students who could have taken both algebra and chemistry?
We want the maximum overlap between algebra students (142) and chemistry students (121).
The overlap is maximized when every chemistry student also took algebra (since 121 < 142, this is possible).
Maximum overlap $= \min(142, 121) = \mathbf{121}$.
Check: if 121 students took both, then students taking at least one subject $= 142 + 121 - 121 = 142 \leq 236$. ✓
So the greatest possible number is $121$.
Angular width $2\theta = \frac{2\lambda}{a} = 60^\circ = \frac{\pi}{3} \text{ rad}$.
$\frac{\lambda}{a} = \frac{\pi}{6} \implies \lambda = \frac{\pi}{6} \times 1 \ \mu\text{m}$.
Fringe width $\beta = \frac{\lambda D}{d} = 1 \text{ cm} = 10^{-2} \text{ m}$.
$d = \frac{\lambda D}{\beta} = \frac{(\pi/6 \times 10^{-6}) \times 0.5}{0.01} \approx 26.1 \ \mu\text{m}$. The closest option is $25 \ \mu\text{m}$.
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