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The internal energy $U$ of a monoatomic gas is $U = \frac{3}{2} nRT = \frac{3}{2} PV$.
First, find the volume $V$ using mass and density: $V = \frac{\text{mass}}{\text{density}} = \frac{2}{8} = 0.25 \text{ m}^3$.
$U = \frac{3}{2} \times (4 \times 10^4) \times 0.25 = 1.5 \times 10^4 = 15000 \text{ J}$.
The order of magnitude is $10^4 \text{ J}$.
In a neutral or weakly alkaline medium, permanganate ($MnO_{4}^{-}$) oxidizes thiosulphate ($S_{2}O_{3}^{2-}$) to sulphate ($SO_{4}^{2-}$). The reaction is:
$8MnO_{4}^{-} + 3S_{2}O_{3}^{2-} + H_{2}O \rightarrow 8MnO_{2} + 6SO_{4}^{2-} + 2OH^{-}$
In the sulphate ion ($SO_{4}^{2-}$), the oxidation state of sulfur is $+6$.
[cite: 13]
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