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3.12 g of oxygen is adsorbed on 1.2 g of platinum metal. Find the volume of oxygen adsorbed per gram of the adsorbent at 1 atm and 300 K.
$[R = 0.0821\ \text{L atm K}^{-1}\ \text{mol}^{-1}]$
Molar mass of O$_2 = 32\ \text{g/mol}$. Moles of O$_2 = \dfrac{3.12}{32} = 0.0975\ \text{mol}$
Total volume at 1 atm, 300 K: $V = \dfrac{nRT}{P} = \dfrac{0.0975 \times 0.0821 \times 300}{1} \approx 2.40\ \text{L}$
Volume per gram of adsorbent (Pt) $= \dfrac{2.40}{1.2} = \mathbf{2.00}\ \text{L g}^{-1}$
Lee and Mia share profits 4:3. Interest on drawings was omitted: Lee $90, Mia $50. By how much will Lee's current account balance decrease when corrected?
Option A ($10) is correct.
Total interest on drawings = $90 + $50 = $140 added to profit available.
Lee's extra profit share = $140 × 4/7 = $80
Net change to Lee's account = −$90 (interest charged) + $80 (extra profit) = −$10
GCS Calculation:
\[\text{GCS} = E + V + M = 2 + 2 + 4 = 8\]
GCS Scoring:
| Domain | Response | Score |
|---|---|---|
| Eye (E) | Spontaneous | 4 |
| To voice | 3 | |
| To pain | 2 | |
| None | 1 | |
| Verbal (V) | Oriented | 5 |
| Confused | 4 | |
| Inappropriate words | 3 | |
| Incomprehensible sounds | 2 | |
| None | 1 | |
| Motor (M) | Obeys commands | 6 |
| Localizes pain | 5 | |
| Withdrawal | 4 | |
| Flexion (Decorticate) | 3 | |
| Extension (Decerebrate) | 2 | |
| None | 1 |
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