Study questions platform-wide or filter by specific tests with correct answers revealed.
The textbook provides specific details about Pakistan's freedom of information framework:
- President Pervez Musharraf promulgated the Freedom of Information Ordinance 2002 in October 2002
- Response timeframe: Government bodies must respond within 21 days
- Applicable bodies: Federal government bodies including ministries, departments, boards, councils, courts, and tribunals
- Excluded: Government-owned corporations and provincial governments — significant gaps in coverage
Contrast this with India's Right to Information Act (2005): response required within 30 days (or 48 hours for matters concerning life and liberty). The textbook is critical of Pakistan's ordinance, noting that “large amounts of information are also not subject to disclosure under the ordinance, largely undermining the public's right to know” and that its restrictive list of disclosable records further limits its effectiveness. This legal knowledge is essential for journalism students understanding press freedom frameworks.
The magnitude of change in velocity is $|\Delta v| = 2v \sin(\frac{\theta}{2})$.
- $|\Delta v| = 2(10) \sin(60^{\circ}/2) = 20 \sin 30^{\circ}$
- $|\Delta v| = 20 \times \frac{1}{2} = 10\text{ m/s}$.
If $0 < st < 1$, then which of the following can be true?
I. $s < -1$ and $t > 0$
II. $s < -1$ and $t < -1$
III. $s > -1$ and $t < -1$
We need $0 < st < 1$, which means $st$ is positive and less than 1.
Check each statement:
I. $s < -1$ and $t > 0$: If $s < -1$ (negative) and $t > 0$ (positive), then $st < 0$ (negative). This violates $st > 0$. ✗
II. $s < -1$ and $t < -1$: Both negative means $st > 0$ ✓. If $s = -2$ and $t = -0.4$, then $st = 0.8$, which satisfies $0 < st < 1$ ✓
Actually, wait. Let's reconsider: if $s < -1$ and $t < -1$, then both are less than $-1$, so both magnitudes are greater than 1. The product would be greater than 1, violating $st < 1$. Let me recalculate: if $s = -1.5$ and $t = -0.5$, then $st = 0.75$, which works. But $t = -0.5$ does not satisfy $t < -1$. If both $s < -1$ and $t < -1$, then $|s| > 1$ and $|t| > 1$, so $|st| > 1$, meaning $st > 1$ since both are negative (making product positive). This violates $st < 1$. ✗
III. $s > -1$ and $t < -1$: This gives us $-1 < s$ and $t < -1$. If $s$ is positive (satisfies $s > -1$) and $t$ is negative with $|t| > 1$, then $st < 0$. ✗ If $s$ is negative with $|s| < 1$ (like $s = -0.5$) and $t < -1$ (like $t = -1.5$), then $st = (-0.5)(-1.5) = 0.75 > 0$ and $< 1$ ✓
Actually, I need to reconsider option I more carefully...
Sign in to join the conversation and share your thoughts.
Log In to Comment